2024 If the points a x 2 b -3 4

If the points a x 2 b -3 4

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WebThe given points A (4, 3) and B (x, 5) lie on the circle with center O (2, 3). Then, OA = OB ⇒ ( x - 2) 2 + ( 5 - 3) 2 = ( 4 - 2) 2 + ( 3 - 3) 2 ⇒ ( x - 2) 2 + 2 2 = 2 2 + 0 2 ⇒ ( x - 2) 2 = ( … WebGiven, A (4, 3) and B (x, 5) are two points on the circle. Centre of the circle is O (2, 3). ∴ OB = OA (Radius of the circle) ⇒ OB2 =OA2 ⇒ (x–2)2+(5–3)2 =(4–2)2+(3–3)2 [Distance formula] ⇒ (x–2)2+4 =4 ⇒ (x–2)2 =0 ⇒ x – 2 = 0 ⇒ x = 2 Thus, the value of x is 2. Suggest Corrections 60 Similar questions Q. If the points (4 2 3 Distance Formula

If the points A x , 2, B 3, 4 and C 7, 5 are collinear, then the value ...

WebFind the midpoint between two points p1 (1,2) and p2 (-4,-3) Tiger Algebra Solver Are you looking for... WebThe given points A (4, 3) and B (x, 5) lie on the circle with center O (2, 3). Then, OA = OB ⇒ ( x - 2) 2 + ( 5 - 3) 2 = ( 4 - 2) 2 + ( 3 - 3) 2 ⇒ ( x - 2) 2 + 2 2 = 2 2 + 0 2 ⇒ ( x - 2) 2 = ( 2 2 - 2 2) ⇒ ( x - 2) 2 = 0 ⇒ x - 2 = 0 ⇒ x = 2 Hence, the value of x = 2 Concept: Coordinate Geometry Is there an error in this question or solution? can be negotiated

If points A (–3, 12), B (7, 6) and C (x, 9) are collinear, then the ...

WebSolution. It is given that the three points A ( x, 2), B (−3, −4) and C (7, −5) are collinear. ∴ Area of ∆ABC = 0. = 1 2 [ x 1 ( y 2 - y 3) + x 2 ( y 3 - y 1) + x 3 ( y 1 - y 2)] = 0. Here and … Web5 jun. 2024 · 5 Answers. Sorted by: 1. f(x) = ax3 − ax2 + bx + 4. Since f(4) = 51 , 51 = a(64 − 16) + 4b + 4 = 48a + 4b + 4 so 12a + b = 47 / 4. Since f(i) = 0 , 0 = a( − i + 1) + ib + 4 = i(b − a) + a + 4 so a + 4 = 0, a = − 4, b − a = 0, b = a = − 4. Therefore f(x) = − 4x3 + 4x2 − 4x + 4. But this does not satisfy f(4) = 51. Web22 jan. 2024 · Answer: The value of x is -63. Step-by-step explanation: The points A (x, 2), B (−3, −4) and C (7, − 5) are collinear, if the slope of AB is equal to the slope of BC. … can benfotiamine cause hair loss

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Web15 mrt. 2024 · asked Mar 15 in Mathematics by HemangRathore (51.2k points) closed Mar 22 by HemangRathore If the points A(x, 2), B(-3, -4) and C(7, -5) are collinear, then the … WebMath Advanced Math 2. [-/3 Points] BBBASICSTAT8COREQ 5.R.013. Does it pay to ask for a raise? A national survey of heads of households showed the percentage of those who asked for a raise and the percentage who got one. According to the survey, of the women interviewed, 25% had asked for a raise, and of those women who had asked for a raise, … fishing fabric panelsWeb14 apr. 2024 · “Ça a vraiment été très lourd” : cette tragédie a marqué Emmanuelle Seigner et Roman Polanski Mariée au réalisateur Roman Polanski depuis 1989, Emmanuelle Seigner a donné une longue … can benfotiamine help vision

"Web28 jan. 2024 · Solution For 16. If the points A(x,2),B(−3,−4) and C(7,−5) are collinear, then find the value of x. Sol. Since A(x,2),B(−3,−4) and C(7,−5) are collinear, \[ \begin{array}{rrr} \therefore & x_{1}\left " - If the points a x 2 b -3 4

If the points a x 2 b -3 4

Web10 apr. 2024 · 2. Le point M centre du quadrilatère ABCE est le point d'intersection des diagonales AC et BE. Pour déterminer ses coordonnées, nous pouvons utiliser le fait que les coordonnées du milieu d'un segment sont données par la moyenne des coordonnées des extrémités. Ainsi, les coordonnées de M sont : xM = (xA + xC + xB + xE)/4 = (-3+2+1-2)/4 ...

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WebFind a relation between x and y, if the points Ax, y, B 5,7 and C 4,5 are collinear. [CBSE 2015] Login. Study Materials. NCERT Solutions. NCERT Solutions For Class 12. NCERT Solutions For Class 12 Physics; NCERT Solutions For Class 12 Chemistry; NCERT Solutions For Class 12 Biology; WebSolution The given points are A (−2, 1), B ( a, b) and C (4, −1). Since the given points are collinear, the area of the triangle ABC is 0. ⇒ 1 2 [ x 1 ( y 2 - y 3) + x 2 ( y 3 - y 1) + x 3 ( y 1 - y 2)] = 0 Here, and x 1 = - 2, y 1 = 1, x 2 = a, y 2 = b and x 3 = 4, y 3 = - 1 ∴ 1 2 [ - 2 ( b + 1) + a ( - 1 - 1) + 4 ( 1 - b)] = 0 -2b-2-2a+4-4b=0

Web20 jul. 2024 · Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto … Web12 nov. 2024 · Best answer Correct Answer - A Here, (x1 = x, y1 = 2), (x2 = − 3, y2 = − 4)and(x3 = 7, y3 = − 5) ( x 1 = x, y 1 = 2), ( x 2 = - 3, y 2 = - 4) and ( x 3 = 7, y 3 = - 5) ∴ x1(y2 − y3) + x2(y3 − y1) + x3(y1 − y2) = 0 ∴ x 1 ( y 2 - y 3) + x 2 ( y 3 - y 1) + x 3 ( y 1 - …

WebIf the points A (4, 3) & B (x, 5) are on the circles with centre O (2, 3), find the value of x. Easy Solution Verified by Toppr Since A and B lie on the circle having centre O. Therefore, OA = OB (4−2) 2+(3−3) 2= ((x−2) 2+(5−3) 2 2= (x−2) 2+4 (x−2) 2+4=4 (x−2) 2=0 x−2=0 x=2 Was this answer helpful? 0 0 Similar questions Web15 mrt. 2024 · asked Mar 15 in Mathematics by HemangRathore (51.2k points) closed Mar 22 by HemangRathore If the points A(x, 2), B(-3, -4) and C(7, -5) are collinear, then the value of x is

Web20 jul. 2024 · Let A(x 1,y 1) = A(x,2), B(x 2,y 2) = B(-3,-4) and C(x 3,y 3) = C(7,-5). So the condition for three collinear points is. Hence, x = -63.

Webthen 2 is a fixed point of f, because f(2) = 2.. Not all functions have fixed points: for example, f(x) = x + 1, has no fixed points, since x is never equal to x + 1 for any real number. In graphical terms, a fixed point x means the point (x, f(x)) is on the line y = x, or in other words the graph of f has a point in common with that line. ... fishing face buffWeb1 jan. 2024 · The given points are A (x, 2) , B (-3, -4) and C (7, -5).The points A, B and C are collinear if area of a triangle formed by joining these points is 0. so, area of Δ ABC = 0 ⇒12 [x1 (y2−y3) + x2 (y3−y1) + x3 (y1−y2)] = 0 ⇒12 [x (−4+5)−3 (−5−2) +7 (2+4)] = 0 ⇒12 [x − 3 (−7)+ 7×6] = 0 ⇒12 [x+21+42] = 0 ⇒12 [x+63] = 0 ⇒x+63 = 0 ⇒x = −63 can benfotiamine cause insomniaWebThe points (2, -1), (-1, 4) and (-2, 2) are the vertices of the sides of a triangle. Find its 4 views New Anil Kumar If a, b, c and d are in proportion, then prove that a - b/c - d... can bengal cats be declawedWeb15 feb. 2024 · If A (x, 2), B (−3, −4), and C (7, −5) are collinear, then the value of x is (A) −63 (B) 63 (C) 60 (D) −60 This question is similar to Ex 7.3, 2 (i) - Chapter 7 Class 10 Coordinate Geometry This video is only available for Teachoo black users Subscribe Now Maths Crash Course - Live lectures + all videos + Real time Doubt solving! can bengal cats eat tunaWebSolution The given points are A (x, 2) , B (-3, -4) and C (7, -5). The points A, B and C are collinear if area of a triangle formed by joining these points is 0. so, area of Δ ABC = 0 … fishing facebook coversWeb20 jul. 2024 · If the points A (2,3), B (5,k) and C (6,7) are collinear then (a) k = 4 (b) k = 6 (c) k = -3/2 (d) k = 11/4 coordinate geometry class-10 1 Answer +1 vote answered Jul 20, 2024 by Anaswara (31.5k points) selected Jul 28, 2024 by Dheeya Best answer Correct answer is (b) k = 6 The given points are A (2,3), B (5,k) and C (6,7). can benfotiamine raise blood pressureWeb28 jan. 2024 · Question. 16. If the points A(x,2),B(−3,−4) and C (7,−5) are collinear, then find the value of x . Sol. Since A(x,2),B(−3,−4) and C (7,−5) are collinear, \ [ \begin … fishing facebook pages